---
数组相关
---

[04. 二维数组中的查找](https://leetcode-cn.com/problems/er-wei-shu-zu-zhong-de-cha-zhao-lcof/)

```java
class Solution {

    public boolean findNumberIn2DArray(int[][] matrix, int target) {
        if (matrix == null || matrix.length == 0) {
            return false;
        }
        int m = matrix.length, n = matrix[0].length;
        int row = 0, col = n - 1;
        while (row < m && col >= 0) {
            if (matrix[row][col] > target) {
                col--;
            } else if (matrix[row][col] < target) {
                row++;
            } else {
                return true;
            }
        }
        return false;
    }
}
```

[11. 旋转数组的最小数字](https://leetcode-cn.com/problems/xuan-zhuan-shu-zu-de-zui-xiao-shu-zi-lcof/)

```java
class Solution {

    public int minArray(int[] numbers) {
        int i = 0, j = numbers.length - 1;
        while (i < j) {
            int m = (i + j) / 2;
            if (numbers[m] > numbers[j]) {
                i = m + 1;
            } else if (numbers[m] < numbers[j]) {
                j = m;
            } else {
                j--;
            }
        }
        return numbers[i];
    }
}
```

[21. 调整数组顺序使奇数位于偶数前面](https://leetcode-cn.com/problems/diao-zheng-shu-zu-shun-xu-shi-qi-shu-wei-yu-ou-shu-qian-mian-lcof/)

```java
class Solution {

    public int[] exchange(int[] nums) {
        int i = 0, j = nums.length - 1;
        while (i < j) {
            if (nums[i] % 2 == 1 && nums[j] % 2 == 0) {
                i++;
                j--;
            } else if (nums[i] % 2 == 1 && nums[j] % 2 == 1) {
                i++;
            } else if (nums[i] % 2 == 0 && nums[j] % 2 == 1) {
                int temp = nums[i];
                nums[i++] = nums[j];
                nums[j--] = temp;
            } else {
                j--;
            }
        }
        return nums;
    }
}
```

```java
class Solution {

    public int[] exchange(int[] nums) {
        int i = 0, j = nums.length - 1, temp;
        while (i < j) {
            while (i < j && (nums[i] & 1) == 1) {
                i++;
            }
            while (i < j && (nums[j] & 1) == 0) {
                j--;
            }
            temp = nums[i];
            nums[i] = nums[j];
            nums[j] = temp;
        }
        return nums;
    }
}
```